The pOH of pure water at 40 degree C is 6.8, then the hydronium ion concentration in pure water at this temperature is 6.3 × 10⁻⁸M.
Relation between the pH and pOH will be represented by the following equation:
pH + pOH = 14
Given that, pOH of water = 6.8
Then pH will be pH = 14 - 6.8 = 7.2
We know that, pH = -log[H⁺]
[H⁺] = [tex]10^{-pH}[/tex]
[H⁺] = [tex]10^{-7.2}[/tex] = 6.3 × 10⁻⁸M
Hence concentration of hydronium ion at that temperature is 6.3 × 10⁻⁸M.
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