The number of molecules of sugar, C₁₂H₂₂O₁₁ you ingest given the data is 6.86×10²² molecules
1 mole of C₁₂H₂₂O₁₁ = 6.02×10²³ molecules
But
1 mole of C₁₂H₂₂O₁₁ = 342 g
Thus,
342 g of C₁₂H₂₂O₁₁ = 6.02×10²³ molecules
342 g of C₁₂H₂₂O₁₁ = 6.02×10²³ molecules
Therefore,
39 g of C₁₂H₂₂O₁₁ = (39 × 6.02×10²³) / 342
39 g of C₁₂H₂₂O₁₁ = 6.86×10²² molecules
Thus, 6.86×10²² molecules are present in 39 g of sugar, C₁₂H₂₂O₁₁
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