The geometry of the softball is a sphere. Then the radius of the softball will be 1.91 inches.
It deals with the size of geometry, region, and density of the different forms both 2D and 3D.
A softball has a volume of about 29 cubic inches.
Then the radius of the softball will be
The geometry of the softball is a sphere.
Then the volume of the sphere is given as
[tex]\rm V = \dfrac{4}{3} \pi r^3[/tex]
where r is the radius of the softball.
Then we have
[tex]\rm r^3 = \dfrac{3V}{ 4 \pi}\\\\r^3 = \dfrac{3 \times 29}{4 \times \pi}\\\\r^3 = \dfrac{87}{12.5664}\\\\r^3 = 6.9232\\\\r \ \ = \sqrt[3]{6.9232}\\\\r \ \ = 1.9059 \approx 1.91 \ in.[/tex]
More about the geometry link is given below.
https://brainly.com/question/7558603
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