The equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.
The equilibrium constant in a chemical reaction is the reaction quotient when the chemical reaction is at equilibrium constant.
The equilibrium constant for the for reaction at 25 °c given in the problem as,
[tex]2A\rightleftharpoons B+C, K_1=1.0 \\2B\rightleftharpoons C+D, K_2=16 \\2C+D\rightleftharpoons 2P, K_3=25 \\[/tex]
Now, the reaction for which the equilibrium constant at 25 °c has to be find out is,
[tex]P\rightleftharpoons A+\dfrac{1}{2}B[/tex]
[tex]K_4=\sqrt{\dfrac{1}{K_1}+\dfrac{1}{K_2}+\dfrac{1}{K_3}}\\K_4=\sqrt{\dfrac{1}{25}+\dfrac{1}{16}+\dfrac{1}{1}}\\K_4=\dfrac{1}{20}[/tex]
Thus, the equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.
Learn more about the equilibrium constant here;
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