The rest energy of the proton will be 938 MeV. The rest energy is related to the rest mass of the proton.
The rest energy is the rest mass times the square of the speed of light of a particle at rest in an inertial frame of reference.
The rest energy is found as;
[tex]\rm E_R= mC^2\\\\ E_R=(1.67 \times 10^{-27})\times 3 \times 10^8)^2\\\\ E_R= 9.375 \times 10^8 / eV[/tex]
Convert into the mega electron volt;
[tex]\rm E_R= 938 \ MeV[/tex]
Hence, the rest energy of the proton will be 938 MeV
To learn more about the rest energy, refer to the link;
https://brainly.com/question/15047418
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