The electric potential at a distance from a nucleus of charge 50e is 144 Volts.
The potential is the work done by the test charge to move it from infinity to a particular point.
The potential is given by the relation
V = kQ / r
The distance of a point from the nucleus is 5.0 × 10⁻¹⁰ m and the charge on the nucleus is 50 e = 50 × 1.9 × 10⁻¹⁹ C.
k = 9 × 10⁹ kg-m²/s²-C²
Here, Q is the charge, r is the distance and k is the constant.
Substituting the value into the equation and solving, we get
V = 144 Volts
Thus, the potential at a distance from a nucleus of charge 50e is 144 Volts.
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