[tex]\Large\textsc{answer :}[/tex]
x≤-7
[tex]\Large\textsc{calculations :}[/tex]
First , use the distributive property :
3(x-4)≥5x+2
3x-12≥5x+2
Subtract 5x on both sides :
3x-5x-12≥2
Now , add 12 on both sides :
3x-5x≥2+12
3x-5x≥14
Subtract the x's :
-2x≥14
Divide by -2 on both sides and watch what happens :
x≤-7 (notice that the inequality sign changed from "greater than or equal to" to "less than or equal to")
If we divide both sides of an inequality by a negative number , we change the inequality sign .
[tex]\footnotesize\textit{hope helpful~}[/tex]
