Answer:
2nd option: 3a-11≤7
Step-by-step explanation:
Step 1: The inequality on the number line is:
[tex]a \leqslant 6[/tex]
Step 2: Take a look at the options. First we know that we want values of a which are less than 6 so we get rid of option 1 and 3.
Step 3: Since 6 is included in the inequality so we need to have a ≤ so 2nd option is correct.
QUICK NOTE: if we solve the inequality shown in the 2nd option we'll see it's gonna be a≤6
take a look:
[tex]3a - 11 \leqslant 7 \\ 3a \leqslant 18 \\ a \leqslant 6[/tex]
