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Calculate the volume of hydrogen gas at 38.0 °C and 763 torr that can be produced
by the reaction of 4.33 g of zinc with excess sulfuric acid.

Respuesta :

solution:

formula= PV = nRT

moles of Zn = 4.33 g Zn x 1 mol Zn/65.4 g

= 0.0662 moles Zn

moles H2 = 0.0662 moles Zn x 1 mol H2/mol Zn

= 0.0662 mole H2 gas

V = nRT/P

T = 38 + 273

= 311K

763 torr/760

= 1.00 atm

V = (0.0662 mol)(0.0821 Latm/Kmol)(311K)/1.00 atm

V = 1.69 L

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