The number of electrons present in -2.8µC of excess electric charge is 1.75 × 10¹³ electrons
From the question, we are to determine the number of electrons present in the given charge
The number of electrons can be determined by using the formula,
[tex]n = \frac{q}{e}[/tex]
Where n is the number of electrons
q is the magnitude of charge
and e is the charge of an electron (e = 1.6 × 10⁻¹⁹ C)
From the given information,
q = 2.8 μC = 2.8 × 10⁻⁶ C
Putting the parameters into the equation, we get
[tex]n = \frac{2.8 \times 10^{-6} }{1.6 \times 10^{-19} }[/tex]
n = 1.75 × 10¹³ electrons
Hence, the number of electrons present in -2.8µC of excess electric charge is 1.75 × 10¹³ electrons
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