Answer:
- [tex]\boxed{\sf{3y^2-y-2}}[/tex]
Step-by-step explanation:
Given:
Isolate the term of y from one side of the equation.
(3y+2)(y-1)
Use the foil method.
[tex]\underline{\text{FOIL METHOD:}}[/tex]
[tex]\Longrightarrow: \sf{\left(A+B\right)\left(C+D\right)=AC+AD+BC+BD}[/tex]
(3y+2)(y-1)=3yy+3y(-1)+2y+2(-1)
Solve.
[tex]\sf{3yy=3y^2}\\\\\\\sf{3y(-1)=-3y}\\\\\\\sf{2(-1)=-2}[/tex]
[tex]\sf{3y^2-3y+2y-2}[/tex]
Add or subtract the numbers from left to right.
Solutions:
[tex]\sf{-3y+2y=-y}[/tex]
[tex]\Longrightarrow: \boxed{\sf{3y^2-y-2}}[/tex]
- Therefore, the correct answer is 3y²-y-2.
I hope this helps. Let me know if you have any questions.
