Answer:
Mean = 75
Median = 73.5
Mode = 95
Range = 36
Step-by-step explanation:
Given:
Sort:
To find:
Mean:
[tex]\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}[/tex]
Sum of all data divides by amount.
[tex]\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}[/tex]
Therefore, mean = 75
Median:
If it’s exact middle then that’s the median. However, if two data or values happen to be in middle:
[tex]\displaystyle \large{\dfrac{x_1+x_2}{2}}[/tex]
From 59,60,70,77,89,95, since 70 and 77 are in middle:
[tex]\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}[/tex]
Therefore, median = 73.5
Mode:
The highest value or/and the highest amount of data. Mode can have more than one.
From sorted data, there are no repetitive data nor same data. Consider the highest value:
Therefore, mode = 95
Range:
[tex]\displaystyle \large{x_{max}-x_{min}}[/tex] or highest value - lowest value
Thus:
[tex]\displaystyle \large{95-59 = 36}[/tex]
Therefore, range = 36