the sum of all interior angles in a polygon is
we know this one is a PENTAgon, so it has 5 sides, so the total for the interior angles will be
180( 5 - 2) = 540 degrees.
540° - 88° - 118° - 132° - 100° = 102° <- fifth angle.
The final interior angle of the pentagon measures 102°.
We know that for a figure of n sides, the sum of its interior angles is equal to:
S = (n - 2)*180°
Then for a pentagon, 5 sides, we have:
S = (5 - 2)*180° = 3*180° = 540°
Then if X is the missing interior angle, we must have:
88° + 118° + 132° + 100° + X = 540°
438° + X = 540°
X = 540° - 438° = 102°
So the measure of the last interior angle is 102°.
If you want to learn more about interior angles:
https://brainly.com/question/24839702
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