The molarity of the NaCl in the 250 ml slat solution is 2.8M.
The molarity of a solution is defined as the concentration of a solute per unit volume of the solution.
Given, the volume of the solution is 250 ml converted into l 0.25
The number of moles of NaCl is 0.70.
By the formula of molarity
[tex]M = \dfrac{n}{V}\\\\\\M = \dfrac{0.70}{0.25} = 2.8 M[/tex]
Thus, the molarity is 2.8 M.
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