Answer:
0.87708moldm-3
Explanation:
[tex]molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\ =159.62gmol {}^{ - 1} \\ mole(n) = \frac{mass}{molar \: mass } \\ n = \frac{35}{159.62} \\ n = 0.21927mol \\ molarity = \frac{n}{v} \\ molarity = \frac{0.21927}{0.25} \\ molarity = 0.87708moldm {}^{ - 3} [/tex]