There are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.
The number of moles of a substance can be calculated by using the following formula:
molarity = no. of moles / volume
According to this question, a volume of 2300 mL solution is contained in 0.68 M MgSO4. The number of moles is calculated as follows:
no of moles = 0.68M × 2.3
no. of moles = 1.56
Therefore, there are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.
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