Answer:
Step-by-step explanation:
[tex]\dfrac{x}{3}+\dfrac{y}{4}=2\\\\\\\text{Multiply the whole equation by the LCM of 4 , 12 which is 12}\\\\ 12*\dfrac{x}{3}+12*\dfrac{y}{4}=12*2\\\\\\4x + 3y=24 \ -------------------(i)[/tex]
[tex]\dfrac{2x}{3}+\dfrac{3y}{4}=5\\\\\\\text{Multiply the whole equation by 12}\\\\12*\dfrac{2x}{3}+12*\dfrac{3y}{4}=5*12\\\\\\[/tex]
8x + 9y = 60 -------------------------(ii)
Multiply equation (i) by (-2)
(i)*(-2) -8x -6y = -48
(ii) 8x +9y = 60 {Now add. x will be cancelled}
3y = 12 {Divide both sides by 3}
y = 12/3
y = 4
Substitute y = 4 in equation (i)
4x + 3*4 = 24
4x + 12 = 24
4x = 24 - 12
4x = 12
x = 12/4
x = 3
[tex]\boxed{x = 3 \ ; \ y = 4}[/tex]
