If 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.
The molarity of a solution can be calculated using the following expression:
M1V1 = M2V2
Where;
25 × 0.80 = 40 × M2
20 = 40M2
M2 = 20/40
M2 = 0.5M
Therefore, if 25 milliliter of 0. 80M HCl is used to completely neutralize 40. milliliters of NaOH solution, the molarity of the base is 0.5M.
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