Answer:
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Step-by-step explanation:
It is given that, the sum of two numbers is 27 and one of the number is 2 times as large as the other.
[tex] \\ [/tex]
Let us assume the one number as x and as state in the question, one of the number is 2 times as large as the other (x) . So, the other number will be 2x .
[tex] \\ [/tex]
Now,
[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + 2x = 27 \:}}} \\ \\[/tex]
Adding like terms we get :
[tex]\\ {\longrightarrow \pmb{\sf {\qquad 3x = 27 \:}}} \\ \\[/tex]
Dividing both sides by 3 we get :
[tex]\\ {\longrightarrow \pmb{\sf {\qquad \frac{3x}{3} = \frac{27}{3} \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\frak {\qquad {x} = {9} \:}}} \\ \\[/tex]
So,
[tex] \\ [/tex]
Now,
[tex] \\ {\longrightarrow \pmb{\frak {\qquad Other \: number = 2x \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 2(9) \:}}} \\ \\[/tex]
[tex]{\longrightarrow \pmb{\frak {\qquad Other \: number = 18 \:}}} \\ \\[/tex]
Therefore,
- The two numbers are 9 and 18.
