[tex]\qquad\qquad\huge\underline{{\sf Answer}}♪[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \:f(x) = g(x)[/tex]
[tex]\qquad \sf \dashrightarrow \:x + 2 = - {x}^{2} + 4[/tex]
[tex]\qquad \sf \dashrightarrow \: {x}^{2} + x + 2 - 4 = 0[/tex]
[tex]\qquad \sf \dashrightarrow \: {x}^{2} + x - 2 = 0[/tex]
[tex]\qquad \sf \dashrightarrow \: {x}^{2} + 2x - x - 2 = 0 [/tex]
[tex]\qquad \sf \dashrightarrow \:x(x + 2) - (x + 2) = 0[/tex]
[tex]\qquad \sf \dashrightarrow \:(x + 2)(x - 1) = 0[/tex]
Hence, x = -2 or x = 1
