The empirical formula of the compound containing 24.78% Carbon, 2.08% Hydrogen, and 73.14% Chlorine is CHCl
Data obtained from the question
- Carbon (C) = 24.78%
- Hydrogen (H) = 2.08%
- Chlorine (Cl) = 73.14%
How to determine the empirical formula
The empirical formula of the compound can be obtained as illustrated below:
Divide by their molar mass
C = 24.78 / 12 = 2.065
H = 2.08 / 1 = 2.08
Cl = 73.14 / 35.5 = 2.06
Divide by the smallest
C = 2.065 / 2.06 = 1
H = 2.08 / 2.06 = 1
Cl = 2.06 / 2.06 = 1
Thus, the empirical formula of the compound is CHCl
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