Respuesta :
[tex]\\ \rm\Rrightarrow 2sin^2x=1-cosx[/tex]
[tex]\\ \rm\Rrightarrow 2sin^2x=1-1+sin^2x[/tex]
[tex]\\ \rm\Rrightarrow 2sin^2x-sin^2x=0[/tex]
[tex]\\ \rm\Rrightarrow sin^2x=0[/tex]
[tex]\\ \rm\Rrightarrow sinx=0[/tex]
[tex]\\ \rm\Rrightarrow x\in n\pi[/tex]
Answer:
I have done this questions before, the answer is C
Step-by-step explanation: