The expression which is equivalent to the provided complex fraction is equal to the expression,
[tex]{\dfrac{-4x+7}{2(x-2)}}[/tex]
Equivalent expressions are the expression whose result is equal to the original expression, but the way of representation is different.
The expression given in the problem is,
[tex]\dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}[/tex]
Let the expression which is equivalent to the above expression is f(x). Therefore,
[tex]f(x)=\dfrac{\dfrac{3}{x-1}-4}{2-\dfrac{2}{x-1}}[/tex]
Take the LCM (x-1) in the numerator and denominator as,
[tex]f(x)=\dfrac{\dfrac{3-4(x-1)}{x-1}}{\dfrac{2(x-1)-2}{x-1}}[/tex]
Simplify the expression and cancel out the (x-1) from both the fraction as,
[tex]f(x)={\dfrac{3-4(x-1)}{2(x-1)-2}}\\f(x)={\dfrac{3-4x+4}{2x-2-2}}\\f(x)={\dfrac{-4x+7}{2(x-2)}}[/tex]
Hence, the expression which is equivalent to the provided complex fraction is equal to the expression,
[tex]{\dfrac{-4x+7}{2(x-2)}}[/tex]
Learn more about the equivalent expression here;
https://brainly.com/question/2972832