Respuesta :

Answer:

[tex]\boxed{-3\left(\sqrt{2}-1\right)}[/tex]

Step-by-step explanation:

[tex]\left(3\sqrt{3-2\sqrt{2}}\right)\left(\sqrt{3}-2\right)\left(\sqrt{3}+2\right)[/tex]

[tex]-3\sqrt{3-2\sqrt{2}}\left(-1\right)[/tex]

[tex]-3\sqrt{3-2\sqrt{2}}[/tex]

[tex]-3\left(\sqrt{2}-1\right)[/tex]

[tex]-3\left(\sqrt{2}-1\right)[/tex]

devishri1977

Answer:

Step-by-step explanation:

[tex](a + b)(a -b) = a^{2}-b^{2}\\\\\\a = \sqrt{3} \ & \ b = 2\\\\(\sqrt{3}-2)(\sqrt{3}+2)=(\sqrt{3})^{2}-2^{2} \\\\ = 3 - 4\\\\= -1[/tex]

[tex](3\sqrt{3-2\sqrt{2}})(\sqrt{3}-2)(\sqrt{3}+2)=(3\sqrt{3-2\sqrt{2}})*(-1)\\ \ = (-3)\sqrt{3-2\sqrt{2}}[/tex]