Respuesta :
[tex]\tt (\dfrac{x}{x+1}.\dfrac{1+x}{2x-1})+\dfrac{1+x}{2x-1}\\\\\dfrac{x}{2x-1}+\dfrac{1+x}{2x-1}=\dfrac{2x+1}{2x-1}[/tex]
Answer:
HOPE IT'S HELP
Step-by-step explanation:
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[tex]\tt (\dfrac{x}{x+1}.\dfrac{1+x}{2x-1})+\dfrac{1+x}{2x-1}\\\\\dfrac{x}{2x-1}+\dfrac{1+x}{2x-1}=\dfrac{2x+1}{2x-1}[/tex]
Answer:
HOPE IT'S HELP
Step-by-step explanation:
ILY
Follow me plsss
thank you