The mass of zinc required to react with HNO3 is 3.45 g
The moles of HNO3 reacting is calculated using the formula below:
volume = 0.850
volume = 125.0 mL = 0.125 L
Moles of HNO3 = 0.850 × 0.125 = 0.10625 moles
Equation of reaction:
Zn + 2 HNO3 --> Zn(NO3)2 + H2
2 moles of HNO3 reacts with 1 mole of Zn.
moles of zinc reacting = 0.10625/2 = 0.053125
Mass of zinc = moles × molar mass
molar mass of Zn = 65
Mass of zinc = 0.053125 × 65
mass of Zn = 3.45 g
Therefore, the mass of zinc will completely react with 125.0 mL of a solution of nitric acid (HNO3) which has concentration of 0.850M is 3.45 g
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