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What is the percentage composition of each element in dinitrogen monoxide, N2O? (4 points)

58.32% N; 41.68% O

60.55% N; 39.45% O

63.64% N; 36.36% O

62.66% N; 37.34% O


I think c

Respuesta :

Answer:A.) 0

Explanation:

Dinitrogen oxygen ()

Valence electrons of oxygen = 6

Valence electron of nitrogen = 5

The total number of the valence electrons  = 2(5) + 6 = 16

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So, The Lewis structure is shown in image below.

Formula for formal charge :

Formal charge for oxygen:

ashish4112119

Answer:

63.64% N; 36.36% O

Explanation:

percentage composition of each element =

Atomic mass of element ÷ molar mass of compound

Nitrogen Atomic mass = 14u

N2 = 28u

molar mass of N20 = 44

28/44 = .6364 = 63.64%

Oxygen Atomic mass = 16u

0 = 16u

molar mass of N20 = 44

16/44 = .3636 = 36.36%

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