Answer:
A = event of rolling a 2 on the first roll
P(A) = 1/6 because there is only one "2" out of six labels total on the number cube.
B = event of rolling an odd number on the second roll
P(B) = 3/6 = 1/2 since there are three odd numbers {1,3,5} out of six total
The events A and B are independent, so we can multiply the probabilities
P(A and B) = probability of both events happening simultaenously
P(A and B) = P(A)*P(B)
P(A and B) = (1/6)*(1/2)
P(A and B) = (1*1)/(6*2)
P(A and B) = 1/12
Final Answer: 1/12
Note: The fraction 1/12 is approximately equal to 0.0833
I hope this helped^.^
May i have brainliest? ^.^
Have a great day buddy! ~hailey
