Answer:
Using the t-distribution, the 99% confidence interval for the true average number of alcoholic drinks all UF female students (over 21) have in a one week period is (3.25, 4.85).
We have the standard deviation for the sample, thus, the t-distribution is used to solve this question.
First, we find the number of degrees of freedom, which is the sample size subtracted by 1, thus:
Then, using a calculator, with and 169 df, we have that the two-tailed critical value is .
The margin of error is:
In this problem, , then:
The confidence interval is:
In this problem, , then:
The confidence interval is (3.25, 4.85).
Step-by-step explanation: