Answer:
Step-by-step explanation:
Using the distance formula,
[tex]AB=\sqrt{(0-2)^{2}+(4-2)^{2}}=2\sqrt{2}\\AC=\sqrt{(0-(-2))^{2}+(4-(-1))^{2}}=\sqrt{29}\\BC=\sqrt{(2-(-2))^{2}+(2-(-1))^{2}}=5[/tex]
So the perimeter is [tex]5+2\sqrt{2}+\sqrt{29}[/tex]