The resistance of the wire is is 36.55 ohms.
The induced emf in the loop is calculated by Faraday's law as follows;
emf = A(B₂- B₁)/t
emf = 0.606 (7.97 - 2.91)/0.856
emf = 3.58 V
The resistance of the wire is calculated by using Ohms law as follows;
emf = IR
R = emf/I
R = 3.58/0.098
R = 36.55 ohms
Learn more about induced emf here: https://brainly.com/question/13744192