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7. A scientist studying a squid observes that the squid at rest
draws in 0.60 kg of water and then ejects that mass
of water back out in 0.15 seconds at a velocity of 15.0 m/s.
What is the average force on the squid during the
propulsion?

Respuesta :

whitneytr12

The average force on the squid during the ejection of 0.60 kg of water at a velocity of 15.0 m/s in 0.15 seconds is 60 N.              

We can calculate the average force with the average acceleration as follows:

[tex] F = m\overline{a} [/tex]   (1)

Where:

  • m: is the mass of water = 0.60 kg
  • [tex]\overline{a} [/tex]: is the average acceleration

The average acceleration is given by the change of velocity in an interval of time

[tex] \overline{a} = \frac{v_{f} - v_{i}}{t_{f} - t_{i}} [/tex]   (2)

Where:

  • [tex]v_{i}[/tex]: is the initial velocity = 0 (the squid is at rest)
  • [tex]v_{f}[/tex]: is the final velocity = 15.0 m/s
  • [tex]t_{i}[/tex]: is the initial time = 0  
  • [tex]t_{f}[/tex]: is the final time = 0.15 s

Now we can find the average force after entering equation (2) into (1)

[tex] F = m(\frac{v_{f} - v_{i}}{t_{f} - t_{i}}) = 0.60 kg(\frac{15.0 m/s - 0}{0.15 s}) = 60 N [/tex]  

Therefore, the average force on the squid during the propulsion is 60 N.

Find more about average force here:

  • brainly.com/question/20902034
  • brainly.com/question/12916904

I hope it helps you!