The number of atoms present in 80.156 grams of Ca is 1.204×10²⁴ atoms
From Avogadro's hypothesis,
1 mole of Ca = 6.02×10²³ atoms
But
1 mole of Ca = 40.078 g
Thus,
40.078 g of Ca = 6.02×10²³ atoms
40.078 g of Ca = 6.02×10²³ atoms
Therefore,
80.156 g of Ca = (80.156 × 6.02×10²³) / 40.078
80.156 g of Ca = 1.204×10²⁴ atoms
Thus, 1.204×10²⁴ atoms is present in 80.156 g of Ca.
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