The area of a rectangle is 5 x cubed + 19 x squared + 6 x minus 18 with length x + 3. Using synthetic division, what is the width of the rectangle?.

Respuesta :

The width of the rectangle using synthetic division is; 5x² + 4x - 6

Synthetic division of Polynomials

We are given;

Area of rectangle = 5x³ + 19x² + 6x - 18

Length of rectangle = x + 3

We know that;

Width of rectangle = Area/length.

Using synthetic division, we have;

             5x² + 4x - 6

  (x + 3) | 5x³ + 19x² + 6x - 18

            -  5x³ + 15x²

                           4x² + 6x

                         - 4x² + 12x

                                   -6x - 18

                                    -6x - 18

                                            0

Thus, the width of the rectangle is 5x² + 4x - 6

Read more about polynomial synthetic division at; https://brainly.com/question/24323423

Answer:

A

Explanation:

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