Triangles are shapes with three sides and angles
The value of B is 16.3 degrees
How to determine the value of B
The given parameters are:
a = 64
b = 18
c = 63
Next, we apply the following cosine formula
[tex]b^2 = a^2 + c^2 - 2ac\ cos(B)[/tex]
So, we have:
[tex]18^2 = 64^2 + 63^2 - 2 * 64 * 63 \ cos(B)[/tex]
Evaluate the exponents
[tex]324 = 8065 - 8064\ cos(B)[/tex]
Collect like terms
[tex]324 - 8065 = - 8064\ cos(B)[/tex]
[tex]-7741 = - 8064\ cos(B)[/tex]
Solve for cos (B)
[tex]\cos(B) =0.9599[/tex]
Take the arccos of both sides
[tex]B =cos^{-1}(0.9599)[/tex][tex]B = 16.3[/tex]
Hence, the value of B is 16.3 degrees
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