The statement that true is (A). All forms of electromagnetic radiation travel at the same speed in a vacuum.
Introduction
Electromagnetic waves have an energy that is carried in energy packets. The energy that was carried is called photon energy. Photon energy is influenced by three factors, namely:
- The speed of light (c), actually the speed of light is a constant (fixed value), if it is in a vacuum. So, when in a vacuum, the value of c will always be the same. The harder the medium through which electromagnetic waves pass, the faster the wave speed will decrease
- Frequency (f), the frequency will be proportional to the energy of the photon carried. The greater the frequency, the more vibrations that occur every second. The heat due to this vibration is part of the photon energy.
- Wavelength ([tex] \sf{\bold{\lambda}} [/tex]), The wavelength of the value will be inversely proportional to the energy of the photon. The shorter the wavelength, the greater the energy of the photons it carries.
Explanation
Based on these concepts, the photon energy equation is obtained as follows :
By Frequency
[tex] \boxed{\sf{\bold{E = h \times f}}} [/tex]
By the Wave Length
[tex] \boxed{\sf{\bold{E = h \times \frac{c}{\lambda}}}} [/tex]
With the following condition :
- E = photon energy (J)
- h = Planck's constant ≈ [tex] \sf{6.6 \times 10^{-34} \: J.s} [/tex]
- c = the constant of the speed of light in a vacuum ≈ [tex] \sf{3 \times 10^{8} \: m/s} [/tex]
- f = electromagnetic wave frequency (Hz)
- [tex] \sf{\lambda} [/tex] = wavelength (m)
Conclusion
So, if you are in a vacuum, only the speed of propagation of electromagnetic waves is the same. Photon energy, only affected by wavelength and/or frequency.
See More :
What is the foton energy https://brainly.com/question/26518899
