Answer:
9.7 ms⁻¹
Explanation:
The formula to find the acceleration is :
[tex]Acceleration=\frac{Final \:Velocity-Initial\:Velocity}{Time}[/tex]
According to the question, we are asked to find the Final Velocity.
For that, let the Final Velocity be x.
[tex]Acceleration=\frac{Final \:Velocity-Initial\:Velocity}{Time}[/tex]
[tex]2m/s^{2} =\frac{x-3.7m/s}{3 s}\\[/tex]
[tex]2 =\frac{x-3.7}{3 }\\[/tex]
[tex]2*3=x-3.7[/tex]
[tex]6=x-3.7[/tex]
[tex]6+3.7=x[/tex]
[tex]9.7=x[/tex]
Therefore,
Final velocity = 9.7ms⁻¹
Hope this helps you :-)
Let me know if you have any other questions :-)
Answer:
9.7m/s
Explanation:
[tex]\pink{\frak{Given}}\begin{cases} \textsf{ Initial velocity of a person is 3.7m/s .}\\\textsf{The acceleration of the person is 2m/s$^2$ .} \end{cases}[/tex]
And we need to find out the velocity of the person after 3 seconds . Here we can use the First equation of motion namely ,
[tex]\sf \longrightarrow v = u + at \\[/tex]
Where ,
Now substitute the respective values in the given equation ,
[tex]\sf \longrightarrow v = 3.7m/s + 2m/s^2*3s\\[/tex]
Simplify ,
[tex]\sf \longrightarrow v = 3.7m/s + 6m/s\\[/tex]
[tex]\sf \longrightarrow \boxed{\bf velocity_{After\ 3 \ s }= 9.7 m/s}\\[/tex]
