A ball is thrown toward the ground. The figure shows the direction of the ball before it reaches the ground and the direction of the ball after it bounces off the ground. After the bounce, the ball leaves the ground with the same speed that it had before the bounce. The angle between the ground and the ball’s direction of travel is θ0 before and after the ball bounces off the ground. The positive directions are indicated in the figure. (a) Each grid below represents a component of the change in momentum of the ball as a result of the bounce. On each grid, draw a vector arrow to indicate the direction and relative magnitude of the change in momentum of the ball as a result of the bounce. If there is no change in momentum for a given component, write "NO CHANGE" under the corresponding grid. (b) A ball of mass M is released from rest at height H1 above the ground. After the ball reaches the ground, it bounces and travels to height H2 (about 1/2 of H1) above the ground, as shown in the figure. In a clear, coherent paragraph-length response that may also contain equations and drawings, explain, using the conservation of momentum and the conservation of energy, why H2

Question

01-02-2022
Physics

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A ball is thrown toward the ground. The figure shows the direction of the ball before it reaches the ground and the direction of the ball after it bounces off the ground. After the bounce, the ball leaves the ground with the same speed that it had before the bounce. The angle between the ground and the ball’s direction of travel is θ0 before and after the ball bounces off the ground. The positive directions are indicated in the figure. (a) Each grid below represents a component of the change in momentum of the ball as a result of the bounce. On each grid, draw a vector arrow to indicate the direction and relative magnitude of the change in momentum of the ball as a result of the bounce. If there is no change in momentum for a given component, write "NO CHANGE" under the corresponding grid. (b) A ball of mass M is released from rest at height H1 above the ground. After the ball reaches the ground, it bounces and travels to height H2 (about 1/2 of H1) above the ground, as shown in the figure. In a clear, coherent paragraph-length response that may also contain equations and drawings, explain, using the conservation of momentum and the conservation of energy, why H2

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mickymike92 mickymike92 · Answer 1 · 2022-02-06T11:53:26+01:00

According to the principle of conservation of momentum, the momentum of the bouncing ball changes.

Also, the ball bounces less than its original height because some energy is lost due to heat, friction and air resistance.

How is momentum conserved in the bounce of balls?

The principle of conservation of momentum states that for any collision occurring in an isolated system, momentum is conserved.

a. For a body such as a ball dropped from a height, the total momentum is conserved.

However, there is a change in momentum of the ball as some of its momentum is transferred to the earth.

b. When the ball a ball of mass M is released from a height H1, it bounces to a height H2, which is about 1/2 of H1.

The value of H2 is less than that of H1 because some of the energy is converted to heat energy due to friction and air resistance, thereby its energy is less than its original value.

Therefore, the momentum of the bouncing ball is changes. Also, the ball bounces less than its original height because some energy is lost due to heat, friction and air resistance.

Learn more about momentum at: https://brainly.com/question/7538238