Answer:
A. 6.32455 inch
B. 71.565°
C. 36.87°
Step-by-step explanation:
A. to find slant height we shall use Pythagoras theorem:
AC^2 = AB^2 + BC^2
AC^2 = 2^2 + 6^2
AC = 6.32455 inch ......... that's the slant height of the cone
B. here we have to find angle A, its where the line segment lies on the base
we use sin cos tan formula
opposite/ adjacent = tan (A)
A = tan^-1(6/2)
=71.565°
C. we have to find the angle where opposite both slant height meets, that's angle C.
as its a right angle triangle we can find half of C° = ( 180° - 90° - 71.565° ) =18.43494882°
So C angle shall be = 18.43494882° * 2
=36.87°
