The value of f(25) and f(-66) are 3 and -4 respectively
Functions and values
Given the function below:
[tex]f(x) = \sqrt[3]{x+2}[/tex]
To get the value of f(25), we will substitute x = 25 into the function to have:
[tex]f(25) = \sqrt[3]{25+2}\\f(25) = \sqrt[3]{27}\\f(25) = 3[/tex]
Similarly for f(-66)
[tex]f(-66) = \sqrt[3]{-66+2}\\f(-66) = \sqrt[3]{-66}\\f(-66) = -4[/tex]
Hence the value of f(25) and f(-66) are 3 and -4 respectively
Learn more on functions here: https://brainly.com/question/10439235
