Answer:
Given that battery V = 12.0 V
Resistance R = 2.0 ohms
a ) current in the battery is I = V /R
= 12.0 V / 2.0
= 6.0 A
b ) charge transported in the circuit is q = i * t
= 6.0 A * 10 s
= 60 C
c ) Work done on the charge by the electric field is 0 ( there is no internal resistance )
d ) work done through the resistor is w = P * t
= ( V)^2 / R * t
= ( 12.0 V )^2 / 2 *10s
= 720J
e ) Total work done is equal to work done through the resistor
W_total = 720 J
f ) there is no internal resistance hence E = 0
