Answer:
[tex]\sf 4(2x-3)=6x+2 \\ \sf{8x - 12 = 6x + 2} \\ \sf{8x - 6x = 2 + 12} \\ \sf{2x = 14} \\ \sf{x = \frac{14}{2} = 7}[/tex]
The value of x from the given equation expression is; x = 7
We are given the equation;
4(2x - 3) = 6x + 2
The first step is to use distributive property to open the bracket to get;
(4 * 2x) - (4 * 3) = 6x + 2
8x - 12 = 6x + 2
Second step is to use subtraction property of equality to add 12 to both sides to get;
8x - 12 + 12 = 6x + 2 + 12
8x = 6x + 14
8x - 6x = 14
2x = 14
x = 14/2
x = 7
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