An isosceles triangle has angle measures (x^2+4) and (22x+12). Find all possible values for x rounded to the nearest hundreth.

Respuesta :

Step-by-step explanation:

As Isosceles triangel has for sure 2 equal angles

and the sum of angles in any triangle is 180

so you have only thes 2 conditions either :

2(x^2+4)+22x+12=180 or 2(22x+12)+(x^2+4)=180

2x^2+8 +22x+12-180=0 or 44x+24+x^2 +4 - 180=0

2x^2+22x-160=0. or x^2+44x-152=0

x1=5 x2=-16. or x3=3.22 x4=-47.22