The polynomial whole zeros are α+β and αβ is x^2 + x - 12
Given the quadratic equation x^2 - 3x - 4 = 0
From the equation, a = 1, b = -3 and c = -4
The sum of the equation α+β = -b/a
α+β = 3/1 = 3
The product of the equation αβ = c/a
αβ = -4/1 = -4
Get the polynomial equation with zeros of 3 and -4
f(x) = (x-3)(x+4)
f(x)= x^2 + 4x - 3x - 12
f(x) = x^2 + x - 12
Hence the polynomial whole zeros are α+β and αβ is x^2 + x - 12
Learn more on roots of quadratic equations here: https://brainly.com/question/776122
