The amount of the unstable isotope that will remain after 6 days is 205 Kg
We'll begin by calculating the the number of half-lives that has elapsed
Half-life (t½) = 3 days
Time (t) = 6 days
Number of half-lives (n) =?
n = t / t(½)
n = 6 / 3
n = 2
Thue, 2 half-lives has elapsed
- Finally, we shall determine the amount remaining.
Number of half-lives (n) = 2
Original amount (N₀) = 820 Kg
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2² × 820
N = 1/4 × 820
N = 0.25 × 820
N = 205 Kg
Thus, 205 Kg of the unstable isotope will remain after 6 days
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