Answer: g > 6
The graph is below
The graph has an open hole at 6; shading to the right
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Explanation:
I'm assuming the variable g is not in the denominator.
To solve for g, we'll first multiply both sides by 3
[tex]-\frac{2}{3}g < -4\\\\3*\left(-\frac{2}{3}g\right) < 3(-4)\\\\-2g < -12\\\\[/tex]
Then divide both sides by -2 to fully isolate g. Dividing both sides by a negative value flips the inequality sign.
[tex]-2g < -12\\\\\frac{-2g}{-2} > \frac{-12}{-2}\\\\g > 6[/tex]
The solution for g is any number larger than 6.
The graph will have an open hole at 6 and shading to the right. See below.
