The volume of base required to completely neutralize the acid is 3.2 mL of NaOH.
The equation of the reaction is;
2NaOH(aq) + H2SO4(aq) -----> Na2SO4(aq) + 2H2O(l)
From the question;
Concentration of acid CA = 0.426M
Concentration of base CB = 2.658M
Volume of acid VA = 10.00mL
Volume of base VB = ?
Number of moles of acid NA = 1
Number of moles of base NB = 2
Using the relation;
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
VB = CAVANB/CBNA
VB = 0.426M × 10.00mL × 2/ 2.658M × 1
VB = 3.2 mL
Learn more: https://brainly.com/question/6111443
