This question involves the concepts of work done, pressure, and temperature.
The work done per mol of the air is "-724.71 J/mol".
Using the given formula for work done:
[tex]W=RTln\frac{P_1}{P_2}[/tex]
where,
W = work done per mol = ?
R = universal gas constant = 8.314 J/mol.k
T = absolute temperature = 30°C + 273 = 303 k
P₁ = initial pressure = 30 KPa
P₂ = final pressure = 40 KPa
Therefore,
[tex]W= (8.314\ J/mol.k)(303\ k)ln\frac{30\ KPa}{40\ KPa}\\[/tex]
W = -724.71 J/mol
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