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Question 2
Which statement best explains
why the sum of the areas of the
two white squares in Figure 2 is
the same as the area of the white
square in Figure 1?

The combined area of the four triangles is equal to the area of the large white
square.
In each triangle, the length of side a plus the length of side b equals the length
of side c. That means that a? + b2 = c?.
In each figure the total area is equal and the area of the 4 triangles is equal, so
the remaining white area in each figure must also be equal.

Question 2 Which statement best explains why the sum of the areas of the two white squares in Figure 2 is the same as the area of the white square in Figure 1 T class=

Respuesta :

reinhard10158

Answer:

the third option

Step-by-step explanation:

that is actually the proof for Pythagoras :

both squares have the total area of (a + b)².

each of the triangles (4 in figure 1, 4 in figure 2) has the same area as the others : a×b/2

so, for figure 1

(a + b)² = 4×a×b/2 + c² = 2×a×b + c²

and for figure 2

(a + b)² = 4×a×b/2 + a² + b² = 2×a×b + a² + b²

2×a×b + c² = 2×a×b + a² + b²

c² = a² + b²

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