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Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground. What is the approximate horizontal component of the initial velocity?

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xEngineerOrg
The horizontal component is calculated as:
Vhorizontal = V · cos(angle)

In your case Vhoriontal = 16 · cos(40) = 12.3 m/s

Answer: 12.3 m/s

The approximate horizontal component of the initial velocity is 12.3 m/s

What is projectile?

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.

Given is Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground.

The horizontal component of the projectile is  

Vx= V cosθ

Substitute the values, we get

Vx  = 16 cos(40) =

Vx =12.3 m/s

Thus, approximate horizontal component of the initial velocity is 12.3 m/s.

Learn more about projectile.

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